Searching
Last updated
Last updated
Sorting search results on a page given a certain set of criteria.
Sort a list of numbers in which each number is at a distance K from its actual position.
Given an array of integers, sort the array so that all odd indexes are greater than the even indexes.
Given users with locations in a list and a logged-in user with locations, find their travel buddies (people who shared more than half of your locations).
Search for an element in a sorted and rotated array.
Sort a list where each element is no more than k positions away from its sorted position.
Search for an item in a sorted, but rotated, array.
Merge two sorted lists together.
Give 3 distinct algorithms to find the K largest values in a list of N items.
Find the minimum element in a sorted rotated array in faster than O(n) time.
Write a function that takes a number as input and outputs the biggest number with the same set of digits.
# linear search O(n)
def name_in_phonebook(to_find, phonebook):
for name in phonebook:
if name == to_find:
return True
return False
# binary search O(log n)
def name_in_phonebook_2(to_find, name):
# sentinal , edge case
if len(to_find) == 0:
return False
# set first element to zero
first = 0
# set the last items to size - 1
last = (len(to_find) - 1)
# set a found flag to false
found = False
# loop until either found or end of list
while first <= last and not found:
# find the middle of the list using interger division //
middle = (first + last) // 2
# if found update found variable
if to_find[middle] == name:
found = True
# otherwise
else:
# if name is to the left of the data
if name < to_find[middle]:
# search the lower half
last = middle - 1
# otherwise
else:
# search the upper half
first = middle + 1
# return found
return foundfrom collections import deque
from collections.abc import Sequence
def bfs_search_grid(grid: Sequence[Sequence[int]], start: tuple[int, int], goal: tuple[int, int]) -> bool:
"""On a grid of 0s and 1s, find if start is connected to goal via a path of 1s."""
rows = range(len(grid))
cols = range(len(grid[0]))
seen = {start}
to_visit = deque([start])
while to_visit:
r, c = to_visit.popleft()
if (r, c) == goal:
return True
adjacent = {(r + 1, c), (r - 1, c), (r, c + 1), (r, c - 1)}
for next_node in adjacent - seen:
r1, c1 = next_node
# Using these range objects is a concise alternative to 0 <= r1 < len(graph) and 0 <= c1 < len(graph[0])
if r1 in rows and c1 in cols and grid[r1][c1]:
seen.add(next_node)
to_visit.append(next_node)
return Falsefrom collections.abc import Callable
def bisect_search(predicate: Callable[[int], bool], low: int, high: int) -> int:
"""Find the lowest int between low and high where predicate(int) is True."""
while low < high:
mid = low + (high - low) // 2 # Avoids integer overflow compared to mid = (low + high) // 2
if predicate(mid):
high = mid
else:
low = mid + 1
return low# Uses python3
import random
"""You're going to write a binary search function.
You should use an iterative approach - meaning
using loops.
Your function should take two inputs:
a Python list to search through, and the value
you're searching for.
Assume the list only has distinct elements,
meaning there are no repeated values, and
elements are in a strictly increasing order.
Return the index of value, or -1 if the value
doesn't exist in the list."""
def binary_search(input_array, value):
test_array = input_array
current_index = len(input_array) // 2
input_index = current_index
found_value = test_array[current_index]
while len(test_array) > 1 and found_value != value:
if found_value < value:
test_array = test_array[current_index:]
current_index = len(test_array) // 2
input_index += current_index
found_value = input_array[input_index]
else:
test_array = test_array[0:current_index]
current_index = len(test_array) // 2
# divmod needed to be used instead of round() since the behavior
# for .5 changed from rounding up to rounding down in Python 3
q, r = divmod(len(test_array), 2.0)
input_index = int(input_index - q - r)
found_value = input_array[input_index]
else:
if found_value == value:
return input_index
return -1
def linear_search(a, x):
for i in range(len(a)):
if a[i] == x:
return i
return -1
# compare naive algorithm linear search vs. binary search results
def stress_test(n, m):
test_cond = True
while test_cond:
a = []
for i in range(n):
a.append(random.randint(0, 10 ** 9))
a.sort()
for i in range(m):
b = random.randint(0, n - 1)
print([linear_search(a, a[b]), binary_search(a, a[b])])
# stops if the searches do not give identical answers
if linear_search(a, a[b]) != binary_search(a, a[b]):
test_cond = False
print("broke here!")
break
stress_test(100, 100000)
# test_list = [1,3,9,11,15,19,29, 35, 36, 37]
# test_val1 = 25
# test_val2 = 15
# print(binary_search(test_list, test_val1))
# print(binary_search(test_list, test_val2))
# print(binary_search(test_list, 11))class BSTNode:
def __init__(self, value):
self.value = value
self.left = None
self.right = None
def insert(self, value):
# create a node for the new value
new_node = BSTNode(value)
# compare the node value to the self value
if (
new_node.value <= self.value
): # less then or equal to will all go to the left if any duplicats too
# we add to the left
if self.left is None:
self.left = new_node
else:
self.left.insert(value)
else:
# we add to the right
# if space exists
if self.right is None:
self.right = new_node
else:
self.right.insert(value)
def search(self, target):
if target == self.value:
return True
# check if value is less than self.value
if target < self.value:
# look to the left
if self.left is None:
return False
return self.left.search(target)
else:
# look to the right
if self.right is None:
return False
return self.right.search(target)
def find_minimum_value(self):
# if self.left is None: #recursive here
# return self.value
# min_value = self.left.find_minimum_value()
# return min_value
curr_node = self
while curr_node.left is not None:
curr_node = curr_node.left
return curr_node.value
root = BSTNode(10)
# root.left = BSTNode(6)
# root.right = BSTNode(12)
root.insert(6)
root.insert(7)
root.insert(12)
root.insert(5)
root.insert(14)
root.insert(8)
print(f"minimum value in tree is: {root.find_minimum_value()}")
print(f"does 8 exist? {root.search(8)}")
print(f"does 8 exist? {root.search(7)}")
print(f"does 8 exist? {root.search(15)}")# -*- coding: utf-8 -*-
"""Searching.ipynb
Automatically generated by Colaboratory.
Original file is located at
https://colab.research.google.com/drive/1Od6PSVwt0pqP6Iko09In0reDVftWMK1F
# Searching
- Linear Search
- Binary Search
## Linear Search
## Binary Search
# Recursion
- iteration
- recursive function
- call stack
"""
"""
Searching (Linear)
"""
# O(n)
data = [12, 23, 1, 34, 56, 100]
target = 10
# starting at the beginning of the data
# take each value and compare that value to a target value
# if they are equal return the index of the target value or return the target value
# if we reach the end of the data, without finding the target then we can return -1
def linear_search(data, target):
for i in range(len(data)):
if data[i] == target:
return (i, data[i])
return -1
print(linear_search(data, target))
"""
Searching (Binary)
"""
# 0 (log(n))
# 0 1 2 3 4 5
data = [12, 23, 45, 67, 99, 200]
target = 99
# keep track of begin and end
# while the begin and end do not overlap
# create a guess index in the middle of the view of data
# check if the data at the guess index is equal to the target
# return (guess_index, guess)
# otherwise is the data at the guess index less than the target
# set the begin to the guess_index + 1
# otherwise
# set end to the guess_index - 1
# if we get here we can not find the target
# return -1
def binary_search(data, target):
begin = 0
end = len(data) - 1
while not end < begin:
guess_index = (end + begin) // 2
if data[guess_index] == target:
return (guess_index, target)
elif data[guess_index] < target:
begin = guess_index + 1
else:
end = guess_index - 1
return -1
print(binary_search(data, target))
"""# CODE: 9356"""
ob
"""# Recursive Functionality
Think of a loop and how that actually works. Now lets think about a function and see how that really works
Let's compare the two...
"""
"""
Looping
"""
import time
n = 10
s = []
start = time.time()
while n > 0: # O(n)
print(n)
n -= 1
end = time.time()
print(f"loop runtime = {end - start}")
"""
Recursive Function
"""
import time
n = 10
def while_rec(n): # O(n)
if not n > 0: # O(1)
return
print(n) # O(1)
while_rec(n - 1) # O(1)
start = time.time()
while_rec(n)
end = time.time()
print(f"func runtime = {end - start}")
# memoization
# generic memo_func
def memo_func(f):
cache = {}
def memo_helper(n):
if n not in cache:
cache[n] = f(n)
return cache[n]
return memo_helper
"""
[ 0, 1, 1, 2, 3, 5, 8]
fib(n) => fib(n - 1) + fib(n - 2)
2
fib(3) => 1 + 1
fib(2) => 1 + 0
fib(1) => 1
fib(0) => 0
fib(1) => 1
"""
from functools import lru_cache
# import sys
# reclim = sys.getrecursionlimit()
# sys.setrecursionlimit(reclim * 10)
# reclim = sys.getrecursionlimit()
print(reclim)
@lru_cache(maxsize=10000)
def fib(n):
if n <= 1:
return n
else:
return fib(n - 1) + fib(n - 2)
@lru_cache(maxsize=1000000)
def fib2(n):
if n <= 1:
return n
else:
return fib(n - 1) + fib(n - 2)
# fib(46)
# memfib = memo_func(fib)
# memfib(46)
fib(460)from collections import deque
from collections.abc import Callable, Iterable, Mapping
from src.typehints import Node
def bfs_search_dict(graph: Mapping[Node, Iterable[Node]], start: Node, predicate: Callable[[Node], bool]) -> bool:
"""Find the closest node to start that matches the predicate using breadth first search."""
visited = set()
to_visit = deque([start])
while to_visit:
node = to_visit.popleft()
if node in visited:
continue
visited.add(node)
if predicate(node):
return True
to_visit += graph[node]
return False